Thanks Michael.
-----Original Message-----
From: Michael Kay [mailto:mike(_at_)saxonica(_dot_)com]
Sent: Wednesday, 18 October 2006 8:37 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] FW: grouping problem
Write a function that decides which group a given value is in
<xsl:function name="my:group">
<xsl:param name="x"/>
<xsl:sequence select="$data/record[start le $x and end ge
$x]/node/type"/>
</
then invoke this function in the group-by expression of
xsl:for-each-group:
<xsl:for-each-group select="tokenize(range,',')" group-by="my:group(.)">
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: SINGH Navpreet [mailto:Navpreet(_dot_)SINGH(_at_)Tenix(_dot_)com]
Sent: 17 October 2006 22:44
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] FW: grouping problem
Still waiting for reply on the following post. Can anyone
help me with this.
thanks.
-----Original Message-----
From: SINGH Navpreet
Sent: Tuesday, 17 October 2006 4:56 PM
To: 'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: grouping problem
Hi all,
Need help with the following problem which I suppose should use
xsl:group in XSLT2.0. What I want to do is to group the result by
<type> element (type1 and type2). Element <range> has all the valid
values and this should be used to find out all values that fall
between <start> and <end> element for each <record>. So expected
result is
type1: 0,2,4,5,6,7
type2: 0,7,8,9,A,B,C,D,E,F
<data>
<range>0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F</range>
<record>
<start>0</start>
<end>0</end>
<node>
<type>type1</type>
</node>
</record>
<record>
<start>0</start>
<end>0</end>
<node>
<type>type2</type>
</node>
</record>
<record>
<start>2</start>
<end>2</end>
<node>
<type>type1</type>
</node>
</record>
<record>
<start>4</start>
<end>7</end>
<node>
<type>type1</type>
</node>
</record>
<record>
<start>7</start>
<end>F</end>
<node>
<type>type2</type>
</node>
</record>
</data>
Thanks.
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