I'm willing to work with you on this, but the XSLT you showed is such an awful
mess that in order for me to spend time on the problem, we'll have to clean it
up no matter that "So hetting these to display correctly on the XSLT is not an
issue."
Based on what I see in your stylesheet, I surmise that you are fairly new to
XSLT, or at least, you haven't had the benefit of training by someone with a
good understanding of the processing model.
So let's start with your first template. I'll quote from the first part:
<xsl:template match="states">
<br/>
<xsl:if test="//state/sym='R'">
Your test tries to establish if there is any "sym" element with a value of "R"
that is a child of a "state" element that my be at any level in the document.
If so then it goes on to create a table.
Is that really what you want to do? Since you say that all "state" elements are
children of one "states" element, there is no point in starting the test
attribute value with two slashes. You could accomplish the same thing, with
less confusion and at less processing cost by replacing your construct with
this one, IF that's what you need to do.
<xsl:template match="states">
<br/>
<xsl:if test="state/sym='R'">
The next question concerns this:
<xsl:for-each select="//state">
<xsl:choose>
<xsl:when test="sym='R'">
Here again you are instructing the processor to find all "state" elements at
whatever level they may be found in the source document. As I said earlier, it
is rare that "xsl:for-each" is required outside of a situation where you need
to sort elements in the output. And you don't seem to be sorting anything here.
It is widely recognized that people new to XSLT who come from an imperative or
procedural programming background are usually puzzled by the processing model
and sieze on "for each" as a familiar landmark. While it usually does what you
want it to do, it is a false friend in that it retards the process of absorbing
the XSLT processing model.
So if what you want is for the stylesheet to process those "state" elements in
your source document that have a "sym" child with a value of "R", your
stylesheet should start like this:
<xsl:template match="states">
<xsl:apply-templates select="state[sym='R']" />
</xsl:template>
<xsl:template match="state">
<tr>
<td><xsl:value-of select="Val1"/></td>
<td><xsl:value-of select="Val2"/></td>
<td><xsl:value-of select="Val3"/></td>
<td><xsl:value-of select="Val4"/></td>
.... Code to deal with external document goes here ....
</tr>
</xsl:template>
Do you want to do anything with "state" elements that have no "sym" child or
have a "sym" child with a value other than "R", or do you wish to omit them
from the output?
I'll continue when we both have an understanding of what's really wanted.
Please advise.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: ms <mina_hurray(_at_)yahoo(_dot_)com>
Sent: Thu, 2 Nov 2006 06:33:02 -0800 (PST)
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: Re: [xsl] formatting issues
Hello:
Thank you all for taking time to go through my
question.
Let me try to explain this.
I have an input file:
<states>
<state>
<sym>R<sym>
<Val1>text<Val1>
<Val2>text<Val2>
<Val3>text<Val3>
<Val4>text<Val4>
<state>
</states>
Now there can be any number of "state" child elements
under "states". The children of "state" are Val1,
Val2, Val3, Val4. So hetting these to display
correctly on the XSLT is not an issue.
Next, we come to the <xsl:apply-templates
select="server/getinfo.dox.../>
This server call returns data in XML format which is:
<results>
<data>
<Val5>something</Val5>
<Val6>something</Val6>
<Val7>something</Val7>
<Val8>P</Val8>
</data>
<data>
<Val5>something</Val5>
<Val6>something</Val6>
<Val7>something</Val7>
<Val8>P</Val8>
</data>
</results>
<data> can be any number inside <results>
The output should be like this. Consider the first
line the headers of the table:
VAL1 VAL2 VAL3 VAL4 VAL5 VAL6 VAL7 VAL8
Text
--- cknell(_at_)onebox(_dot_)com wrote:
I'll try to help, but first I need the answers to
some questions.
The first template matches the element "states"
========================== > <xsl:template match="states">
<br/>
<xsl:if test="//state/sym='R'">
... content omitted for clarity ...
</xsl:template>
========================== >
In your source XML document, is "states" the parent
of all "state" elements, or do some "state" elements
have "state" child elements?
Further along in this template you have this:
========================== > <xsl:for-each select="//state">
========================== >
Unless you are planning to sort the elements, you
probably don't need xsl:for-each, just use
xsl:apply-templates.
Further along still you have this:
========================== > <td><xsl:choose>xsl:value-of select="Val3"/></td>
========================== >
Why do you have an opening xsl:choose without a
closing tag and no xsl:when or xsl:otherwise within?
Still further along you have this:
========================== > <xsl:apply-templates
select="document(concat($server,'/getinfo.dox?...........)"/>
========================== >
Just what is it you are trying to get by
concatenating the value of the variable or paramater
$server with the string "'/getinfo.dox?..........."?
These problems aside, if your real XSLT works at all
then it must be legal XML, which your sample is
clearly not. I suspect your problem lies in these
templates:
<xsl:template match="data/Val5">
<td><xsl:value-of select="."/></td>
</xsl:template>
<xsl:template match="data/Val6">
<td><xsl:value-of select="node()"/></td>
</xsl:template>
<xsl:template match="data/Val7">
<td><xsl:value-of select="node()"/></td>
</xsl:template>
<xsl:template match="data/Val8">
<td><xsl:value-of select="node()"/></td>
</xsl:template>
If the root element of the document you are getting
with
<xsl:apply-templates
select="document(concat($server,'/getinfo.dox?...........)"/>
is "data", then you have omitted the document root
from the "match" attribute.
The correct XPath for these would begin with "/", as
in match="/data/Val8".
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: ms <mina_hurray(_at_)yahoo(_dot_)com>
Sent: Wed, 1 Nov 2006 12:45:41 -0800 (PST)
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] formatting issues
Hi:
Can someone please reply to this ? I have been
pretyt
frustrated with this problem and would really
appreciate if anyone can help.
--- ms <mina_hurray(_at_)yahoo(_dot_)com> wrote:
I have tried everything possible and have failed
to
format this XML.
My XSLT looks like this:
<xsl:template match="states">
<br/>
<xsl:if test="//state/sym='R'">
<table width="100%">
<tr>
<td colspan="8">
<b>STATES: </b>
</td>
</tr>
<tr>
<td width="9%">
<u>Val1</u>
</td>
<td width="15%">
<u>Val2</u>
</td>
<td width="7%">
<u>Val3</u>
</td>
<td width="7%">
<u>Val4</u>
</td>
<td width="9%">
<u>Val5</u>
</td>
<td width="21%">
<u>Val6</u>
</td>
<td width="15%">
<u>Val7</u>
</td>
<td width="7%">
<u>Val8</u>
</td>
</tr>
<xsl:for-each select="//state">
<xsl:choose>
<xsl:when test="sym='R'">
<tr>
<td>
<xsl:value-of select="Val1"/>
</td>
<td>
<xsl:value-of select="Val2"/>
</td>
<td>
<xsl:choose>
<xsl:value-of select="Val3"/>
</td>
<td>
<xsl:value-of select="Val4"/>
</td>
<xsl:variable
name="v1">
<xsl:value-of select="Val1"/>
</xsl:variable>
<xsl:variable
name="v2">
<xsl:value-of select="Val2"/>
</xsl:variable>
<xsl:apply-templates
select="document(concat($server,'/getinfo.dox?...........)"/>
</tr>
</xsl:when>
</xsl:choose>
</xsl:for-each>
</table>
</xsl:if>
</xsl:template>
<xsl:template match="results">
<tr>
<xsl:apply-templates/>
</tr>
</xsl:template>
<xsl:template match="data">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="data/Val5">
<td>
<xsl:value-of select="."/>
</td>
</xsl:template>
<xsl:template match="data/Val6">
<td>
<xsl:value-of select="node()"/>
</td>
</xsl:template>
<xsl:template match="data/Val7">
<td>
<xsl:value-of select="node()"/>
</td>
</xsl:template>
<xsl:template match="data/Val8">
<td>
<xsl:value-of select="node()"/>
</td>
</xsl:template>
=== message truncated ==
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