There are two common forms of identity transform. The one with
<xsl:template match="node()|@*">
relies on xsl:copy to copy the text nodes
The one with <xsl:template match="*"> relies on the built-in template rule
for text nodes to copy the text nodes.
But in either case, you can write a template rule for text nodes:
<xsl:template match="text()" priority="10">
<xsl:value-of select="." disable-output-escaping="yes"/>
</xsl:template>
that will override the default.
Though why on earth you would want to disable output escaping on all the
text in your document defeats me.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Peter Szinek [mailto:peter(_at_)rubyrailways(_dot_)com]
Sent: 15 November 2006 18:04
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Identify transform with disabled output escaping
Hello all,
I have been browsing the archives for at last 2 hours and
could not find the answer - though it seems so trivial.
I have found some older messages claiming that the identify
transformation can not be done without xsl:copy. However,
disable-output-escaping is valid for xsl:value and xsl:text
only (i.e. not for xsl:copy). For me, these two statements
imply that the identify transformation can not be done with
output escaping disabled.
Is there a workaround for this?
Thanks,
Peter
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail:
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--