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RE: [xsl] Enumerating elements using a relative path

2006-11-21 13:35:30
The code you've shown us looks fine. This usually means that the error is in
the code you haven't shown us.

Michael Kay
http://www.saxonica.com/
 

-----Original Message-----
From: David Nesbitt [mailto:dnesbitt(_at_)vuetechnology(_dot_)com] 
Sent: 21 November 2006 20:09
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Enumerating elements using a relative path

I am confused about how elements get accessed using a 
relative path from the context node.

Suppose the following XML:

<a>
      <b>
              <d>1</d>
              <d>2</d>
              <d>3</d>
      </b>
      <c/>
</a>

If element "c" is my context node, I try to do the following:

<xsl:for-each select"../b/d">

I see to get 1, 2, and then 1 again, instead of 1, 2, 3.  Am 
I missing something with how to enumerate these "d" elements 
using a relative path?

Regards,
Dave

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