My Sincerest apologizes, I accidentally sent this to the xml list.
Hi List,
Thanks in advance for the help. I think I left my brain in Cuba, and
cannot seem to figure out this fairly straight forward problem (well
that and secretly hoping someone has a more elegant way of doing
this).
So I have a generated XML
<root>
<view>
<id>foo</id>
<name>foo</name>
</view>
<view>
<id>bar_archive</id>
<name>Bar Archive</name>
</view>
<view>
<id>bar</id>
<name>bar</name>
</view>
<view>
<id>foo_archive</id>
<name>Foo Archive</name>
</view>
</root>
Issue comes from the fact that every time I get this XML file, the
<view>s are in different, random order. I need them in a specific
order every time. Along with this, sometimes a <view> exists, and
sometimes it doesn't which should be reflected in the output. So far
my XSL looks something like this (I've marked where my if statement is
failing):
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<html>
<body>
<!-- This if statement fails (Value of expression cannot be converted
to a node-set in expression) -->
<xsl:if test="root//view/id = 'foo' | root//view/id = 'bar'">
<p>Here are the foo bars</p>
<ul>
<xsl:apply-templates select="root//view[id='bar']"/>
<xsl:apply-templates select="root//view[id='foo']"/>
</ul>
</xsl:if>
<xsl:if test="contains(root//view/id, 'archive')">
<p>Here are archive foo bars</p>
<blockquote>
<xsl:apply-templates select="root//view[id = 'bar_archive']"/>
<xsl:apply-templates select="root//view[id = 'foo_archive']"/>
</blockquote>
</xsl:if>
</body>
</html>
</xsl:template>
<xsl:template match="view" priority="5">
<li><xsl:value-of select="name"/></li>
</xsl:template>
<xsl:template match="view[contains(id, 'archive')]" priority="10">
<p><xsl:value-of select="name"/></p>
</xsl:template>
</xsl:stylesheet>
Any thoughts would be greatly appreciated. (PS - I am stuck with 1.0)
Thanks you,
Spencer Tickner
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