At 05:01 PM 12/19/2006, you wrote:
A quick and dirty way:
<xsl:if test="position() = 1">
<div>
<xsl:value-of select="AgencyName"/>
</div>
</xsl:if>
This will display AgencyName only on the first occurrence of the nodes
selected by your key.
Not really. It'll display AgencyName only if the current node of the
instruction is the first node among the current node list --
something which only has to do with the order of the nodes you select
by your key if you control for this. If you don't, and it works, it's
working by accident.
Note, however, that your key only groups by
FilingType--if you have multiple AgencyNames with the same FilingType
only the first occurrence of AgencyName will appear.
You can fix this by expanding your key:
<xsl:key name="tar_by_filingtype" match="MonthlyTARList"
use="concat(FilingType, ' ', AgencyName)"/>
Then change your for-each to use
key('tar_by_filingtype', concat(FilingType, ' ', AgencyName))
Using an explicit for-each instruction around the xsl:if clause will
provide the needed control to make sure position() works properly ...
but it's then safer just to select the first one in document order explicitly:
<xsl:for-each
select="key('tar_by_filingtype', concat(FilingType, ' ', AgencyName))[1]">
<!-- note predicate in select expression -->
<div>
<xsl:value-of select="AgencyName"/>
</div>
</xsl:for-each>
Cheers,
Wendell
======================================================================
Wendell Piez
mailto:wapiez(_at_)mulberrytech(_dot_)com
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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