Re: [xsl] XSLT Solution for hyphenation

Yes, i'm doing an exact match. I was thinking of using keys but i don't 
know how to use it for these kind of look-up, i'm more familiar with 
using keys in grouping.
Suppose i have this input:

<root>
   <p>I have some text that has the words abaissassent and abandonnent.</p>
</root>

How do i use keys so that i can have this output?

<root>
   <p>I have some text that has the words abais&#00AD;sassent and 
aban&#00AD;donnent.</p>
</root>

heres a sample of the look-up table:

<root>
<wordlist>
  <entry>
    <search>abaissassent</search>
    <replace>abais&#x00AD;sassent</replace>
  </entry>
  <entry>
    <search>abaissèrent</search>
    <replace>abais&#x00AD;sèrent</replace>
  </entry>
  <entry>
    <search>abandonnent</search>
    <replace>aban&#x00AD;donnent</replace>
  </entry>
</wordlist>
</root>

-- Jeff


Michael Kay wrote:
> You seem to be doing exact matching on the words in your dictionary, not
> regular expression matching as your use of matches() would suggest. With
> exact matching you can use a key for the lookup which will be dramatically
> faster.
>
> Michael Kay
> http://www.saxonica.com/ 
>
>   
> > -----Original Message-----
> > From: Jeff Sese [mailto:jsese(_at_)asiatype(_dot_)com] 
> > Sent: 22 December 2006 06:10
> > To: Xsl-List
> > Subject: [xsl] XSLT Solution for hyphenation
> >
> > Hi list,
> >
> > I have this project that applies hyphenation to an XML 
> > document using a list of words as a reference. The list of 
> > words can reach up to a million entries.
> > My XSLT solution was having a template that matches text() 
> > nodes then insert hyphens to the matching words that are in 
> > the list. However the transformation takes to long to finish 
> > even for a relatively small file (around 1mb). Is there 
> > anyway to speed this or is there a better solution?
> > Here's my stylesheet:
> >
> > <xsl:template match="/">
> >     <xsl:apply-templates/>
> > </xsl:template>
> > <xsl:template match="@*|element()|comment()|processing-instruction()">
> >     <xsl:copy>
> >         <xsl:apply-templates select="@*|node()"/>
> >     </xsl:copy>
> > </xsl:template>
> > <xsl:template match="text()">
> >     <xsl:variable name="str" select="."/>
> >     <xsl:variable name="searchStrs" as="xs:string*" 
> > select="$search-words[matches($str,.)]/replace(.,'[.\\?*+{}()\
> >     
> [\]\^\$&#x007C;]',
>   
> > '\\$0')"/>
> >     <xsl:value-of 
> > select="ati:replace-all($str,$searchStrs,$replaceStr)"/>
> > </xsl:template>
> > <xsl:function name="ati:replace-all">
> >     <xsl:param name="input" as="xs:string"/>
> >     <xsl:param name="words-to-replace" as="xs:string*"/>
> >     <xsl:sequence select="if (exists($words-to-replace)) then 
> > ati:replace-all(replace($input, $words-to-replace[1],
> > key('replace',$words-to-replace[1],$search-words)),remove($wor
> >     
> ds-to-replace,1))
>   
> > else $input"/>
> > </xsl:function>
> >
> > heres a sample of the look-up table:
> >
> > <root>
> >     <wordlist>
> >         <entry>
> >             <search>abaissassent</search>
> >             <replace>abais&#x00AD;sassent</replace>
> >         </entry>
> >         <entry>
> >             <search>abaissèrent</search>
> >             <replace>abais&#x00AD;sèrent</replace>
> >         </entry>
> >         <entry>
> >             <search>abandonnent</search>
> >             <replace>aban&#x00AD;donnent</replace>
> >         </entry>
> >     </wordlist>
> > </root>
> >
> > so if i have a "abaissassent" in a text() node this will be 
> > replaced with "aban&#x00AD;donnent".
> > --
> > *Jeff*
> >
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