I asume you could use something like this
(the answer is seperate templates and "apply-templates")
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">
<xsl:template match="/">
<html>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
<xsl:template match="para">
<p>
<xsl:apply-templates/>
</p>
</xsl:template>
<xsl:template match="break">
<br />
</xsl:template>
<xsl:template match="image">
<img src="{(_at_)src}"/>
</xsl:template>
</xsl:stylesheet>
with apply-templates you pass the childnodes to the templates
cheers
Geert
At 21:38 29/12/2006, you wrote:
Please show us what the "obvious HTML" looks like.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Guy <guy(_at_)deltat1(_dot_)com>
Sent: Fri, 29 Dec 2006 10:12:40 -0500
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: [xsl] Processing inner elements
This must be a trivial question but I cannot find any reference to the
standard way of processing this. Here is a fragment of XML:
<para>This is a sentence<break/>
<image src=http://site.com/image/image.jpg/><break/>
And a second sentence.
</para>
Assuming that you are at the <para> node, how does one typically transform
that into the obvious HTML that is required?
I know that a straight <xsl:value-of...> and <xsl:copy-of...> will not work.
Thanks!
Guy
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