Yes, your example is correct. I don't know if or how many PIs will
occur at the end of the node.
P.S. I started a new post because they changed the requirements....
----- Original Message -----
From: Abel Braaksma <abel(_dot_)online(_at_)xs4all(_dot_)nl>
Date: Thursday, January 4, 2007 9:53 am
Subject: Re: [xsl] targeting the last element in a node or consecutive
elements
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Hi Emily,
This is a double post, you already opened this discussion under
"suppressing only the last PI" (which differed in details, however).
If I may, it appears that you want to do this:
<somenode>
<node1 />
<?instr1?>
<node2 />
<?instr2?>
<?instr3?>
</somenode>
1. Process node1, instr1, node2 etc
2. Do something before instr2 and instr3 (being consecutively and
together at the end of a node)
3. Process instr2 and instr3
(if instr2 and instr3 were not there, you want to skip processing
step 2
and 3?)
Am i right? Please confirm (and/or give your sample input, to make
the
subject easier)
Cheers,
-- Abel
Emily(_dot_)Garrett(_at_)thomson(_dot_)com wrote:
I'm trying to use xsl:apply templates to grab the entire content
of a
node, except for any PIs that may be at the very end of the
node. I can
see how position()=last() can be used to refer to the very last
PI, but
how would I refer to possibly 2 or 3 PIs that are at the end of
the node
(not knowing what they are or how many), but still process PIs
that are
contained elsewhere in this content? Is there some syntax that
refers> to consecutive elements or refers to an element that is
the last one in
a node, not knowing what element it is?
Here is explanation for what I'm trying to do:
Process all content, unless they are PIs that occur
consecutively at the
very end of the node.
Then I have to insert an element, then process these PIs that occur
consecutively at the very end of the node.
I'm having trouble narrowing down my research on this one. Does
anyone> have any ideas?
Thanks,
Emily
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