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RE: [xsl] Using xsl:sort causes transformer to fail

2007-01-20 10:01:24
1. What do you mean when you say it "fails" or "doesn't work"? What are the
symptoms?

2. What does the source XML look like?

3. It looks a very strange sort key, what are you trying to achieve?

Michael Kay
http://www.saxonica.com/


-----Original Message-----
From: Sola Awe [mailto:sodana(_at_)hotmail(_dot_)com] 
Sent: 20 January 2007 15:29
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Using xsl:sort causes transformer to fail

Hi,
  I have an xsl:sort expression that doesn't always work all 
the time.  Not sure why.  Here is a segment of my code:

------------------------
xsl:for-each select="$group/ITEM">
  <xsl:sort 
select="*[name()=$group/ITEM/*[name()=$rowKey]]/@*[name() = 
$sortBy]" order="{$sortOrder}" data-type="number"/>

  <xsl:if test="*[name()=$group/ITEM/*[name()=$rowKey]]">
    <xsl:call-template name="processItem">
      <xsl:with-param name="columnNode"       select="$columnNode"/>
      <xsl:with-param name="dataGroup"        select="$group"/>
      <xsl:with-param name="rowKey"           
select="*[name()=$rowKey]"/>
      <xsl:with-param name="repeatName"       
select="attribute::SORTNAME"/>                
</xsl:call-template>
  </xsl:if>
</xsl:for-each>

----------------------------------
This is the code that is failing:
  <xsl:sort 
select="*[name()=$group/ITEM/*[name()=$rowKey]]/@*[name() = 
$sortBy]" order="{$sortOrder}" data-type="number"/>

if, I remove the following from the xsl:sort,

*[name()=$group/ITEM/*[name()=$rowKey]]/

The xsl transformation works fine.  However, I need the code 
above for the sort to work.

Any suggestions?
Thanks.



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