Owen
Not sure but none of Microsoft's products support XSLT 2.0 so I'm surprised
you got as far as that with Visual Studio.
Joe
----- Original Message -----
From: "Owen Blacker" <owen(_at_)blacker(_dot_)me(_dot_)uk>
To: "XSL list" <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Friday, January 26, 2007 1:56 PM
Subject: [xsl] Type error? Too many items?
I'm developing using Altova XMLSpy 2006 Visual Studio .NET Edition (rel 3
SP1) and my XSLT is complaining about "Type error, value does not match a
required type as specified by the matching rules in 2.5.4 SequenceType
Matching. - 'node()'", yet if I put a watch on the XPaths "." and "../*",
they are exactly the types I'd expect (a node() and a node()* of length
~20), if I set a breakpoint at the xsl:call-template statement.
Then, if I remove the as attributes on the xsl:with-param elements, it
tells me "Too many items" on the xsl:if. I really can't see what's going
on here.
Any suggestions greatfully received!
Owen
XSLT excerpts:
<xsl:call-template name="module-bodies">
<xsl:with-param name="current-position"
select="foo:index-of-node(., ../*)"/>
<xsl:with-param name="future-position"
select="foo:index-of-node(following-sibling::h3, ../*)"/>
</xsl:call-template>
...
<xsl:function name="foo:index-of-node" as="xs:integer*">
<xsl:param name="srch" as="node()"/>
<xsl:param name="sequence" as="node()*"/>
<xsl:for-each select="$sequence">
<xsl:if test=". is $srch">
<xsl:sequence select="position()"/>
</xsl:if>
</xsl:for-each>
</xsl:function>
XML:
<div>
<h3> ... </h3>
<p> ... </p>
<p> ... </p>
<h3> ... </h3>
<p> ... </p>
<p> ... </p>
<!-- etc --->
</div>
--
Owen Blacker, London GB
Say no to ID cards: www.no2id.net
Get your mitts off my bits: www.openrightsgroup.org
--
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