xsl-list
[Top] [All Lists]

RE: [xsl] many-to-many

2007-01-29 12:40:32
What I meant to say was...
That is exactly what I had in mind. Thank you.
Quite a bit cleaner than any example I was able to find on the web
(but maybe I was looking in the wrong places).
However, I've been away from XSL for a while - and wasn't ever real good at it.
I haven't figured out yet how the 'part' template works yet and 
I don't see how I would output elements (e.g., partLoc below) along with the 
part id.
It's simple, right? (ducking qand running)

 <doc>
   <invoices>
     <invoice id="i1">
         <date>01/01/07</date>
       <part id="1"/>
       <part id="2"/>
     </invoice>
     <invoice id="i2">
         <date>01/01/07</date>
       <part id="5"/>
       <part id="2"/>
     </invoice>
     <invoice id="i3">
         <date>01/01/07</date>
       <part id="5"/>
       <part id="3"/>
     </invoice>
     <invoice id="i4">
         <date>01/02/07</date>
       <part id="5"/>
       <part id="2"/>
     </invoice>
     <invoice id="i5">
         <date>01/01/07</date>
       <part id="3"/>
       <part id="4"/>
     </invoice>
   </invoices>
   <parts>
        <part name="part1" id="1">
                <partLoc>A</partLoc>
        </part>
        <part name="part2" id="2">
                <partLoc>B</partLoc>
        </part>
        <part name="part3" id="3">
                <partLoc>C</partLoc>
        </part>
        <part name="part4" id="4">
                <partLoc>D</partLoc>
        </part>
   </parts>
 </doc>

Ronan Klyne wrote:
I read the many-to-many problem as two one-to-many problems, 
one in each
direction, for which keys are a good solution.
As far as I know, it is not possible to use a key in reverse, so two
keys must be used; one for each direction.

I include an example involving parts and invoices. Is this the kind of
thing you had in mind?

      # r

----- Input data:
<doc>
  <invoices>
    <invoice id="i1">
      <part id="1"/>
      <part id="2"/>
    </invoice>
    <invoice id="i2">
      <part id="5"/>
      <part id="2"/>
    </invoice>
    <invoice id="i3">
      <part id="5"/>
      <part id="3"/>
    </invoice>
    <invoice id="i4">
      <part id="5"/>
      <part id="2"/>
    </invoice>
    <invoice id="i5">
      <part id="3"/>
      <part id="4"/>
    </invoice>
  </invoices>
  <parts>
    <part name="part1" id="1"/>
    <part name="part2" id="2"/>
    <part name="part3" id="3"/>
    <part name="part4" id="4"/>
  </parts>
</doc>

----- Stylesheet:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="html" indent="no" encoding="ISO-8859-1"/>

<xsl:key name="p-i" match="/doc/invoices/invoice" use="part/@id"/>
<xsl:key name="i-p" match="/doc/invoices/invoice/part" use="../@id"/>

<xsl:template match="invoice">
  <h3>invoice <xsl:value-of select="@id"/> contains:</h3>
  <xsl:for-each select="key('i-p', @id)">
    part <xsl:value-of select="@id"/>
  </xsl:for-each>
</xsl:template>

<xsl:template match="part">
  <h3>part <xsl:value-of select="@id"/> was part of invoices:</h3>

  <xsl:for-each select="key('p-i', @id)">
    <xsl:value-of select="@id"/>
  </xsl:for-each>
</xsl:template>

<xsl:template match="doc">
  <h2>invoice to parts</h2>
  <xsl:apply-templates select="invoices/*"/>
  <h2>part to invoices</h2>
  <xsl:apply-templates select="parts/*"/>
</xsl:template>

</xsl:stylesheet>

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>