Re: [xsl] Wrap changing element sequence into container: with 'for-each-

Thank you very much for both suggestions. So if I understand right I 
either have to resort to something which looks to me like "recursion 
into groups", applying xsl:for-each-group to the result of all previous 
groupings, or I have to set up a kind of table of grouping keys on which 
to branch.
A third approach came to my mind. When the order of elements in the flat 
sequence is fixed, the series of xsl:apply-templates instructions that 
process the remaining elements may be interrupted by the necessary 
xsl:for-each-group instructions, which then can immediately select the 
elements they have to group. Like this:
<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:output indent="yes"/>

  <xsl:template match="root">
    <xsl:copy>
      <xsl:apply-templates/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="flatsequence">
    <hierarchy>

      <xsl:apply-templates select="a"/>

      <xsl:for-each-group
        select="b|c" group-adjacent="1">
        <container1>
          <xsl:copy-of select="current-group()"/>
        </container1>
      </xsl:for-each-group>

      <xsl:apply-templates select="d|e|f"/>

      <xsl:for-each-group
        select="g|h|i" group-adjacent="1">
        <container2>
          <xsl:copy-of select="current-group()"/>
        </container2>
      </xsl:for-each-group>

      <xsl:apply-templates select="j"/>

    </hierarchy>
  </xsl:template>

  <xsl:template match="a|d|e|f|g|h|i|j">
    <xsl:copy>
      <xsl:apply-templates/>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>


That seems to work, but perhaps I am missing something?
(If it's OK as it is: any idea how to specify the grouping criterion, 
which just has to evaluate as permanently true, more elegantly than 
using 'group-adjacent="1"'?)
  Yves


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