xsl-list
[Top] [All Lists]

Re: [xsl] Xpath expression for nested elements with same name

2007-02-01 11:48:56
Hi Simon,

<xsl:copy-of select="//g[(_at_)id='match_this']/*"/>

Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com

Simon Shutter wrote:
Hello,

This is my first post. I have an XML document
<svg>
 <g>
  <g id='match_this'>
   <g>
    <rect x="100" y="100" width="10" height="10" />
    <rect x="300" y="100" width="10" height="10" />
    <rect x="500" y="100" width="10" height="10" />
   </g>
  </g>
 </g>
</svg>

I would like to return all nodes that are descendents of <g
id='match_this'>.  Can you help with the path expression please?  I would
like to return the node set

   <g>
    <rect x="100" y="100" width="10" height="10" />
    <rect x="300" y="100" width="10" height="10" />
    <rect x="500" y="100" width="10" height="10" />
   </g>


Thanks, Simon


--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--


--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>