So now the *REAL* challenge exists in what Dr. Kay pointed out in a
follow-up comment to that same thread
[http://blogs.msdn.com/mfussell/archive/2004/05/13/130969.aspx#131098 ],
> It's a little bit odd to try and prove your point with an example
that makes no use of XML input or XML output,
Which, of course, I completely looked over as well with my original post.
Gentleman? ;-)
On Mon, 05 Feb 2007 06:04:59 -0700, Andrew Welch
<andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com> wrote:
On 2/5/07, Abel Braaksma <abel(_dot_)online(_at_)xs4all(_dot_)nl> wrote:
Andrew Welch wrote:
> After seeing M. David's post about the bottles of beer problem, I
> thought about how to solve this problem using XSLT 2.0. Here's what
> came to mind first:
Hi Andrew,
let me try what came to mind second ;)
Here's my go on it in a single XPath statement. A bit less well-suited
for educational purposes. It shows nested for-loops in XPath, casting,
use of sequences+separator and some ways how not to code (it is exactly
an example of good programming practice ;)
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";>
<xsl:output method="text" />
<xsl:template match="/" name="main">
<xsl:value-of select="
for $i in reverse(1 to 99)
return for $j in
(' on the wall.',
'. Take one down, pass it around',
' on the wall. ' )
return concat
($i - xs:integer(ends-with($j, ' ')),
' bottle', if ($i = 1) then '' else 's',
' of beer', $j)
" separator=" "/>
</xsl:template>
</xsl:stylesheet>
Nice! However a couple of small problems:
2 bottles of beer on the wall.
2 bottles of beer.
Take one down, pass it around
1 bottles of beer on the wall.
^^^^^^^
1 bottle of beer on the wall.
1 bottle of beer.
Take one down, pass it around
0 bottle of beer on the wall.
^^^^^^^^
You just need to modify it slightly:
<xsl:value-of select="for $i in reverse(1 to 3), $j in
(' on the wall.',
'. Take one down, pass it around',
' on the wall. ' )
return concat
($i - xs:integer(ends-with($j, ' ')),
' bottle', if ($i - xs:integer(ends-with($j,
' ')) = 1) then '' else 's',
' of beer', $j)"
separator=" "/>
which gives:
2 bottles of beer on the wall.
2 bottles of beer.
Take one down, pass it around
1 bottle of beer on the wall.
1 bottle of beer on the wall.
1 bottle of beer.
Take one down, pass it around
0 bottles of beer on the wall.
cheers
andrew
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
--
/M:D
M. David Peterson
http://mdavid.name | http://www.oreillynet.com/pub/au/2354
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--