Srinivasan,
If you have any control over the XML format it may help to decide whether to
use attributes or elements.
As a quick fix you can use //@ to select all child attributes. It's a bit
blunt but it works.
Your XML is.
<state_results state_name="Atlantic Canada" state_id="AC">
<game_results game_name="Lotto 6/49" game_id="201">
<date>
<abbr_date>02/03/07</abbr_date>
<full_date>02/03/2007</full_date>
</date>
<number_str>10-13-24-27-37-39, Bonus: 14</number_str>
<numbers>
<number>10</number>
<number>13</number>
</numbers>
<bonus>
<bonus_name>Bonus</bonus_name>
<bonus_number>14</bonus_number>
</bonus>
<next_date>
<next_abbr_date>02/07/07</next_abbr_date>
<next_full_date>02/07/2007</next_full_date>
</next_date>
</game_results>
<requested_action>ADD</requested_action>
</state_results>
It have repeated it here because it is easier to see the format.
For test purposes I have:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:template match="state_results">
<table border="1">
<tbody>
<tr>
<th>name</th>
<th>value</th>
</tr>
<xsl:for-each select="//@*">
<tr>
<td>
<xsl:value-of
select="name()"/>
</td>
<td>
<xsl:value-of
select="."/>
</td>
</tr>
</xsl:for-each>
</tbody>
</table>
Desired output
<table border="1">
<tbody>
<tr>
<th>name</th>
<th>value</th>
</tr>
<tr>
<td>state_name</td>
<td>Atlantic Canada</td>
</tr>
<tr>
<td>state_id</td>
<td>AC</td>
</tr>
<tr>
<td>game_name</td>
<td>Lotto 6/49</td>
</tr>
<tr>
<td>game_id</td>
<td>201</td>
</tr>
<tr>
<td>abbr_date</td>
<td>02/03/07</td>
</tr>
<tr>
<td>full_date</td>
<td>02/03/2007</td>
</tr>
<tr>
<td>number_str</td>
<td>10-13-24-27-37-39, Bonus:
14</td>
</tr>
<tr>
<td>next_abbr_date</td>
<td>02/07/07</td>
</tr>
</tbody>
</table>
</xsl:template>
</xsl:stylesheet>
As you can see the child of child elements are not matched.
If you can change the elements to attributes like:
<date abbr_date="02/03/07" full_date="02/03/2007"/>
Then you will find it works.
William Charlton
The yMonda team
yMonda Limited
w: www.ymonda.net
-----Original Message-----
From: Thangavelu Srinivasan [mailto:vasantry(_at_)gmail(_dot_)com]
Sent: 2007 February 16 12:20
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Extracting element name and value as separate
Hi Folks
I am using xslt 1.0. I am facing the problem in extracting the element
name and value separately. Any suggestions are welcome
Sample XML:
<state_results state_name="Atlantic Canada" state_id="AC">
- <game_results game_name="Lotto 6/49" game_id="201">
- <date>
<abbr_date>02/03/07</abbr_date>
<full_date>02/03/2007</full_date>
</date>
<number_str>10-13-24-27-37-39, Bonus: 14</number_str>
- <numbers>
<number>10</number>
<number>13</number>
</numbers>
- <bonus>
<bonus_name>Bonus</bonus_name>
<bonus_number>14</bonus_number>
</bonus>
- <next_date>
<next_abbr_date>02/07/07</next_abbr_date>
<next_full_date>02/07/2007</next_full_date>
</next_date>
</game_results>
<requested_action>ADD</requested_action>
</state_results>
My XSL:
<xsl:stylesheetxmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:template match="state_results">
<xsl:for-each select="@*">
<Name><xsl:value-of select="name()"/></Name>
<Value><xsl:value-of select="."/></Value>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Required Output :
<Name>state_name</Name>
<Value>Atlantic Canada</Value>
<Name>state_id</Name>
<Value>AC</Value>
<Name>game_name</Name>
<Value>Lotto 6/49</Value>
<Name>game_id</Name>
<Value>201</Value>
<Name>abbr_date</Name>
<Value>02/03/07</Value>
<Name>full_date</Name>
<Value>02/03/2007</Value>
<Name>number_str</Name>
<Value>10-13-24-27-37-39, Bonus: 14</Value>
<Name>next_abbr_date</Name>
<Value>02/07/07</Value>
I am not able to get desired output.
Regards
Srinivas
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