The implementation of exsl:node-set() in Saxon 6.x is a bit of a hack. A
result tree fragment in Saxon 6.x is a document node, with a special bit set
to say "I am a result tree fragment": this bit artifically disables
operations such as "/" applied to the document node. The effect of
exsl:node-set() is to unset this bit in situ, thus enabling such operations.
A bit dirty, but the XSLT spec allows extension functions to do anything you
like, so it's not technically non-conformant.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Manfred Staudinger
[mailto:manfred(_dot_)staudinger(_at_)gmail(_dot_)com]
Sent: 21 February 2007 22:21
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] exsl:node-set and Saxon 6.5.5
Hi All,
As I rely heavily on the superb diagnostics of Saxon when
testing client-side (browser) XSLT 1.0 I would like to
understand the following.
When I run the stylesheet below with SAXON 6.5.5 (with two
<xsl:copy-of statements) then the (unexpected) output is
<?xml version="1.0" encoding="utf-8"?>
<test>
<Title>From exsl:node-set($rtf)/a/b:</Title>
<b>
<c>
<d/>
</c>
</b>
<Title>Directly from $rtf/a/b/c:</Title>
<c>
<d/>
</c>
</test>
However, if I delete the first <xsl:copy-of then I get this
error message from the other one
To use a result tree fragment in a path expression, either
use exsl:node-set() or specify version='1.1'
as I think correctly.
Did I miss something XSLT-wise ?
Regards, Manfred
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0"
xmlns:exsl="http://exslt.org/common";
exclude-result-prefixes="exsl"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output indent="yes"/>
<xsl:template match="/">
<xsl:variable name="rtf">
<a>
<b>
<c>
<d />
</c>
</b>
</a>
</xsl:variable>
<test>
<Title><xsl:text>From
exsl:node-set($rtf)/a/b:</xsl:text></Title>
<xsl:copy-of select="exsl:node-set($rtf)/a/b"/>
<Title><xsl:text>Directly from
$rtf/a/b/c:</xsl:text></Title>
<xsl:copy-of select="$rtf/a/b/c"/>
</test>
</xsl:template>
</xsl:stylesheet>
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