a 2.0 solution would be great, thx for your time, i have been working
with xsl-fo for a time, but never had to do complicated
transformations like this one, i want to learn all i can from you ;)
2007/3/8, Michael Kay <mike(_at_)saxonica(_dot_)com>:
I'm guessing from your choice of element names that your hierarchic
structure is positional rather than defined by pointers.
This makes it a positional grouping problem. Such problems are always much
easier in XSLT 2.0, so you need to make it clear whether you want a 1.0 or a
2.0 solution.
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: SEXpeare [mailto:sexpeare(_at_)gmail(_dot_)com]
> Sent: 08 March 2007 10:20
> To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> Subject: [xsl] Transforming a non-hierarchical XML into a
> hierarchical one
>
> Hello everybody, I have to transform a non hierarchical XML:
>
> <sumario>
> <seccion txt=""/>
> <subseccion txt=""/>
> <organismo txt=""/>
> <anuncio txt=""/>
> <organismo txt=""/>
> <anuncio txt=""/>
> <organismo txt=""/>
> <anuncio txt=""/>
> <subseccion txt=""/>
> <organismo txt=""/>
> <anuncio txt=""/>
> <seccion txt=""/>
> <subseccion txt=""/>
> <organismo txt=""/>
> <anuncio txt=""/>
> ...
> </sumario>
>
> into a hierarchical XML, doing this via XSLT. The result must
> be like this:
>
> <sumario>
> <seccion id="">
> <subseccion id="">
> <organismo id="">
> <anuncio>
> </anuncio>
> ...
>
> </organismo>
> </subseccion>
> </seccion>
> ...
> </sumario>
>
> I would apreciate any idea or advice, thx.
>
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