So you have several worksheets.
How many rows do you have on each input worksheet?
How many rows do you want on each of the output worksheets?
Do all worksheets have the same number of rows?
Do you want all rows output on a single worksheet?
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Ram Shan <hellodck(_at_)hotmail(_dot_)com>
Sent: Tue, 13 Mar 2007 09:26:44 -0600
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: RE: [xsl] Sorting Problem with Xml and Xsl
I guess I should have explained a little better. I want I want to sort all
the elements with in ALL worksheets (NOT JUST BY EACH worksheet 's Cell
values). please check the example
Consider this input XML:
-------------------------------
<?xml-stylesheet type="text/xsl" href="excelsort.xsl" ?>
<?mso-application progid='Excel.Sheet'?>
<s:Workbook xmlns:s="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:o="urn:schemas-microsoft-com:office:office">
<s:Worksheet s:Name="Sample1">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">B</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">C</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
<s:Worksheet s:Name="Sample2">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">D</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">A</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
</s:Workbook>
--------------------------
The output I wanted is:
<?xml-stylesheet type="text/xsl" href="excelsort.xsl" ?>
<?mso-application progid='Excel.Sheet'?>
<s:Workbook xmlns:s="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:o="urn:schemas-microsoft-com:office:office">
<s:Worksheet s:Name="Sample1">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">A</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">B</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
<s:Worksheet s:Name="Sample2">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">C</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">D</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
</s:Workbook>
------------------------------
Please NOTE: the text in <s:Data s:Type="String"></s:Data> for each of the
worksheets re-ordered and need to be sorted accross all worksheets in
workbook. Yes, the one you posted does WORK...but only WITH IN worksheet
nodes. Thanks for your time. Appreciate your help
Thanks
Ram
From: cknell(_at_)onebox(_dot_)com
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: RE: [xsl] Sorting Problem with Xml and Xsl
Date: Tue, 13 Mar 2007 09:59:34 -0400
With exception of
1) omitting the s:Name attribute on the s:Worksheet element,
2) omitting this processing instruction: <?mso-application
progid='Excel.Sheet'?>
the stylesheet I posted produces exactly what you gave as the desired
output.
If you add this:
<xsl:template match="s:Worksheet">
<s:Worksheet>
<xsl:copy-of select="@*" /> <--- Add this element
you will get a copy of any attributes for the s:Worksheet element in the
output.
Each worksheet gets its rows sorted based on the string value of the s:Data
elements.
If this is not what you want, please state explicitly what it is that you
want, or show an example of the output you want. The output generated by
the stylesheet I posted does match what you have already given as the
desired output, so perhaps you should examine the sample output closely to
determine if you have stated the requirement correctly.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Ram Shan <hellodck(_at_)hotmail(_dot_)com>
Sent: Mon, 12 Mar 2007 15:06:51 -0600
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Sorting Problem with Xml and Xsl
Thanks for the quick response. Please note that I am a newbie to xsl and
just trying to get a feel of it. But, with the solution you posted, it
sorts
with in the worksheet nodes only. I want to sort all the <s:Data
s:Type="String"></s:Data> elements text with in all the worksheets, so for
example
my input file
-------------------
<?xml version='1.0'?>
<?mso-application progid='Excel.Sheet'?>
<s:Workbook xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:s="urn:schemas-microsoft-com:office:spreadsheet">
<s:Worksheet s:Name="Sample1">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">RJTGOVBVHX</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">IEXGTQYSBQ</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
<s:Worksheet s:Name="Sample2">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">WUGRDFHDTV</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">PQFWLWQYQW</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
</s:Workbook>
the output that I want to show is
--------------------------------------------
<?xml version='1.0'?>
<?mso-application progid='Excel.Sheet'?>
<s:Workbook xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:s="urn:schemas-microsoft-com:office:spreadsheet">
<s:Worksheet s:Name="Sample1">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">IEXGTQYSBQ</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">PQFWLWQYQW</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
<s:Worksheet s:Name="Sample2">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">RJTGOVBVHX</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">WUGRDFHDTV</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
</s:Workbook>
Thanks
Ram
From: cknell(_at_)onebox(_dot_)com
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Sorting Problem with Xml and Xsl
Date: Mon, 12 Mar 2007 16:25:12 -0400
Your stylesheet doesn't match your input document. You left out several
layers of nested elements.
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:s="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:strip-space elements="*" />
<xsl:output method="xml" indent="yes" encoding="UTF-16" />
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="s:Workbook">
<s:Workbook xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:s="urn:schemas-microsoft-com:office:spreadsheet">
<xsl:apply-templates />
</s:Workbook>
</xsl:template>
<xsl:template match="s:Worksheet">
<s:Worksheet>
<xsl:apply-templates />
</s:Worksheet>
</xsl:template>
<xsl:template match="s:Table">
<s:Table>
<xsl:for-each select="s:Row">
<xsl:sort select="s:Cell/s:Data" />
<xsl:copy-of select="." />
</xsl:for-each>
</s:Table>
</xsl:template>
</xsl:stylesheet>
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Ram Shan <hellodck(_at_)hotmail(_dot_)com>
Sent: Mon, 12 Mar 2007 13:27:04 -0600
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Sorting Problem with Xml and Xsl
I can not get this sorting to work. any help is greatly appreciated. I am
using MSXml parser and c# to transform. Thanks
Here is Sample XML
-------------
<?xml-stylesheet type="text/xsl" href="rowextrated2.xsl" ?>
<?mso-application progid='Excel.Sheet'?>
<s:Workbook xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:s="urn:schemas-microsoft-com:office:spreadsheet">
<s:Worksheet s:Name="Sample1">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Maa</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Baa</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Aaa</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
<s:Worksheet s:Name="Sample2">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Caa</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Qaa</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Zaa</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
</s:Workbook>
--------------My Xsl looks like this. But the problem is it does not take
get me the sorted out . please check below
<?xml version="1.0" encoding="utf-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:s="urn:schemas-microsoft-com:office:spreadsheet" version="1.0">
<xsl:output method="xml" indent="yes" encoding="utf-16"/>
<xsl:template match="s:Workbook">
<xsl:copy>
<xsl:apply-templates>
<xsl:sort data-type="text" select="s:Cell/s:Data"
case-order="lower-first" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
---Desired output
<?xml-stylesheet type="text/xsl" href="rowextrated2.xsl" ?>
<?mso-application progid='Excel.Sheet'?>
<s:Workbook xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:s="urn:schemas-microsoft-com:office:spreadsheet">
<s:Worksheet s:Name="Sample1">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Aaa</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Baa</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Caa</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
<s:Worksheet s:Name="Sample2">
<s:Table>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Maa</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Qaa</s:Data>
</s:Cell>
</s:Row>
<s:Row>
<s:Cell>
<s:Data s:Type="String">Zaa</s:Data>
</s:Cell>
</s:Row>
</s:Table>
</s:Worksheet>
</s:Workbook>
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