Thanks! I was working on this in the background before
I got a chance to read the replies and came up with
pretty much the exact same solution... :) I added in
ignoring text nodes also.
<?xml version="1.0" encoding="utf-8"
standalone="yes"?>
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0"
encoding="utf-8" omit-xml-declaration="yes"
standalone="no" indent="no" media-type="text/xml"/>
<xsl:template match="/">
/*--- ---*/
<xsl:apply-templates/>
/*--- ---*/
</xsl:template>
<xsl:template match="node()">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="name(.)"/><xsl:text> </xsl:text>
<xsl:if test="@id">#<xsl:value-of
select="@id"/><xsl:text> </xsl:text></xsl:if>
<xsl:if test="@class">.<xsl:value-of
select="@class"/><xsl:text> </xsl:text></xsl:if>
</xsl:for-each>
<xsl:text>{ }
</xsl:text>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="text()">
<xsl:apply-templates/>
</xsl:template>
</xsl:transform>
I'll have to take a closer look at Michael Kay's
response too. I'm using xslt 1.0 for now but maybe
the 
 is better?
XSLT 1.0 or 2.0? Here's a 2.0 solution, untested:
<xsl:template match="*">
<xsl:apply-templates
select="ancestor-or-self::*/(.|@class|@id)"
mode="token"/>
<xsl:text>
</xsl:text>
</xsl:template>
<xsl:template match="*" mode="token">
<xsl:value-of select="concat(name(), ' ')"/>
</xsl:template>
<xsl:template match="@class" mode="token">
<xsl:value-of select="concat('.', ., ' ')"/>
</xsl:template>
<xsl:template match="@id" mode="token">
<xsl:value-of select="concat('#', ., ' ')"/>
</xsl:template>
Michael Kay
http://www.saxonica.com/
--- Jay Bryant <jay(_at_)bryantcs(_dot_)com> wrote:
Hello,
I searched for this all over and couldn't find a
solution. I want to take the following XML:
<root>
<file>
<element/>
</file>
<file id="a">
<element id="a"/>
</file>
<file class="b">
<element class="b"/>
</file>
<file id="c" class="d" not="1" this="2">
<element id="c" class="d" not="1" this="2"/>
</file>
</root>
#### and output something this ####
root
root file
root file element
root file #a
root file #a element #a
root file .b
root file .b element .b
root file #c .d
root file #c .d element #c .d
#### ignoring any attributes that are not "id" or
"class" and containing all ancestor elements and
id's
and classes no matter what the element name is or
how
many levels deep. I'd like to use this for auto
generating CSS declarations from XHTML snipits, I
can
deal with removing redundant rows manually. Below
is
the closest I've gotten which only strips the XML
to
the elements and attributes I'm interested in, but
doesn't format it or list ancestor elements, id's
and
classes (I'm a beginner at XSLT) thanks! ####
<xsl:template match="node()|@id|@class">
<xsl:copy>
<xsl:apply-templates select="node()|@id|@class"/>
</xsl:copy>
</xsl:template>
Here's one way:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="text" indent="no"/>
<xsl:template match="*">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="name()"/><xsl:text>
</xsl:text>
<xsl:if test="@id">#<xsl:value-of
select="@id"/><xsl:text>
</xsl:text></xsl:if>
<xsl:if test="@class">.<xsl:value-of
select="@class"/><xsl:text>
</xsl:text></xsl:if>
</xsl:for-each>
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
Jay Bryant
Bryant Communication Services
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