On 3/28/07, Angela Williams
<Angela(_dot_)Williams(_at_)the401kcompany(_dot_)com> wrote:
Aha!
My esteemed colleague came up with a better idea - gosh, I hate it when
I forget the power of xpath!
<?xml version="1.0" encoding="UTF-8"?>
<employees>
<employee hireDate="04/23/1999">
<last>Hill</last>
<first>Phil</first>
<salary>100000</salary>
</employee>
<employee hireDate="09/01/1998">
<last>Herbert</last>
<first>Johnny</first>
<salary>95000</salary>
</employee>
<employee hireDate="08/20/2000">
<last>Hill</last>
<first>Graham</first>
<salary>89000</salary>
</employee>
<sort order="1">last</sort>
<sort order="2">first</sort>
</employees>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0" xmlns:saxon="http://saxon.sf.net/">
<xsl:output method="text" />
<xsl:template match="employees">
<xsl:variable name="sort1" select="sort[(_at_)order='1']" />
<xsl:variable name="sort2" select="sort[(_at_)order='2']" />
<xsl:variable name="sort3" select="sort[(_at_)order='3']" />
<xsl:variable name="sort4" select="sort[(_at_)order='4']" />
<xsl:for-each select="employee">
<xsl:sort
select="if ($sort1) then saxon:evaluate($sort1) else 'foo'" />
<xsl:sort
select="if ($sort2) then saxon:evaluate($sort2) else 'foo'" />
<xsl:sort
select="if ($sort3) then saxon:evaluate($sort3) else 'foo'" />
<xsl:sort
select="if ($sort4) then saxon:evaluate($sort4) else 'foo'" />
Last: <xsl:apply-templates select="last" />
First: <xsl:apply-templates select="first" />
Salary: <xsl:apply-templates select="salary" />
Hire Date: <xsl:apply-templates select="@hireDate" />
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Here's a way of sorting dynamically without extensions:
<?xml version="1.0"?>
<xsl:stylesheet version="2.0"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fn="fn">
<xsl:variable name="employees" select="/employees/employee"/>
<xsl:variable name="sortValues" select="/employees/sort" as="xs:string+"/>
<xsl:function name="fn:performSort" as="element()+">
<xsl:param name="list" as="element()+"/>
<xsl:param name="sortKey" as="xs:string+"/>
<xsl:variable name="sortedList" as="element()+">
<xsl:for-each select="$list">
<xsl:sort select="*[name() = $sortKey[1]]"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
<xsl:sequence select="if ($sortKey[2]) then
fn:performSort($sortedList, subsequence($sortKey, 2))
else $sortedList"/>
</xsl:function>
<xsl:template match="/">
<xsl:sequence select="fn:performSort($employees, $sortValues)"/>
</xsl:template>
</xsl:stylesheet>
You call the performSort() function with a list of elements to sort,
and a list of child element names to sort with, and it recursively
sorts by each one.
hope this helps,
cheers
andrew
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--