What you said works great. except that it outputs <testnode
att1="1,2,3,4" att2="a'b'c'd' /> 4 times instead of one
I want it to output only once.
In the whole xslt file that I have I am using your idea with the only
change of <xsl:template match="//testnode"> instead
of match="/"
PS:This is my second day into XSL and I am going thru the tutorials also
but I have to finish this XSL thing today. Bear
with me :)
-----Original Message-----
From: Abel Braaksma [mailto:abel(_dot_)online(_at_)xs4all(_dot_)nl]
Sent: Thursday, March 29, 2007 4:47 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] concatenate multiple attribute values and assign it
to another attribute
Shaikh, Parvez wrote:
<test node att1="1" att2="a" />
<test node att1="2" att2="b" />
<test node att1="3" att2="c" />
<test node att1="4" att2="d" />
I want to output this as
<testnode att1="1,2,3,4" att2="a,b,c,d" />
How do you do this.
Well, that won't change my original answer, here is it applied to your
testdata:
<xsl:template match="/">
<testnode>
<xsl:attribute name="att1">
<xsl:apply-template select="//test/@att1" />
</xsl:attribute>
<xsl:attribute name="att2">
<xsl:apply-template select="//test/@att2" />
</xsl:attribute>
</testnode>
</xsl:template>
<xsl:template match="@att1 | @att2">
<xsl:value-of select="." />
<xsl:text>,</xsl:text>
</xsl:template>
<xsl:template match="@att1[last()] | @att2[last()]">
<xsl:value-of select="." />
</xsl:template>
Good luck with coding,
Cheers,
-- Abel Braaksma
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