THe following transformaton s a straightforward solutionto this proble:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:variable name="vDoc1" as="document-node()"
select="document('file:///C:/XSLT/Tests/docFoo1.xml')"/>
<xsl:variable name="vDoc2" as="document-node()"
select="document('file:///C:/XSLT/Tests/docFoo2.xml')"/>
<xsl:template match="/">
<foo>
<xsl:for-each-group select="($vDoc1 | $vDoc2)/*/bar"
group-by="@id">
<xsl:sort select="current-grouping-key()"/>
<xsl:sequence select="."/>
</xsl:for-each-group>
</foo>
</xsl:template>
</xsl:stylesheet>
--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play
On 4/17/07, Scott Lynch <slynch(_at_)nortel(_dot_)com> wrote:
This probably isn't the easiest way to this (suggestions welcome), but
I'm collecting data from two similarly structured source documents and
wanting to build a set of distinct nodes based on a certain attribute
value. Example XML:
doc1.xml
<foo>
<bar id="a" />
<bar id="b" />
<bar id="c" />
<bar id="d" />
<bar id="g" />
</foo>
doc2.xml
<foo>
<bar id="a" />
<bar id="b" />
<bar id="c" />
<bar id="d" />
<bar id="e" />
<bar id="f" />
</foo>
Desired resulting node set:
<foo>
<bar id="a" />
<bar id="b" />
<bar id="c" />
<bar id="d" />
<bar id="e" />
<bar id="f" />
<bar id="g" />
</foo>
I'm required to provide a template function (or equivalent set of
templates which returns a node set for use by various for-each
constructs in other processors) which accepts the xpath (e.g. /foo/bar)
and an index attribute (e.g. "id") as parameters and returns a node set
as seen above.
I've managed to write a function which generates a sorted union (I think
I need them sorted to find the distinct values, correct? sorry, newbie
here..), but have yet to find a way to trim the results set so that it
contains only distinct members. Here's what I have so far:
<xsl:variable name="compare_file" select="document('doc2.xml')"/>
<xsl:variable name="current_file" select="document('doc1.xml')"/>
<xsl:function name="con:distinct_rows">
<!-- Selects the distinct rows from the source docs and -->
<!-- comparison doc -->
<xsl:param name="path"/>
<xsl:param name="key"/>
<xsl:variable name="source_rows"
select="$current_file/saxon:evaluate($path)"/>
<xsl:variable name="compare_rows"
select="$compare_file/saxon:evaluate($path)"/>
<xsl:variable name="sorted_union_rows">
<xsl:for-each select="$source_rows | $compare_rows">
<xsl:sort data-type="text" select="./saxon:evaluate($key)"/>
<xsl:sequence select="."/>
</xsl:for-each>
</xsl:variable>
<xsl:sequence select="$sorted_union_rows"/>
<!-- ??? distinct node selector instead ??? -->
</xsl:function>
Once I have the sorted union, I've tried various following/previous
sibling selectors but have yet to find a command which generates the
distinct node set (I can find the unique nodes based on the "id" but
that's not really helping me).
Any suggestions?
thanks a lot!
Scott Lynch
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