Start with a recursive copy template then match the text nodes and
process the new lines, for instance replace them with spaces:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="text()">
<xsl:value-of select="translate(., ' ',' ')"/>
</xsl:template>
</xsl:stylesheet>
Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina - http://aboutxml.blogspot.com/
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com
Senthilkumaravelan K wrote:
Hi
I want to flatten the XML node structure to single line,
I tried indent=no and it does not work for me.
Please any suggestions.
I use the following xslt
<?xml version="1.0" encoding='UTF-8'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="no" />
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
input
<node1>
</Item1>
</Item1>
</Item1>
</Item1>
</Item1>
</Item1>
</Item1>
</node1>
output
<node1></Item1></Item1></Item1>..</node1>
Regards,
Senthil
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