RE: [xsl] Finding the path to a node

  <xsl:template match="/">
    <xsl:apply-templates select="pages//page[(_at_)id='4']" />
  </xsl:template>

  <xsl:template match="page">
    <xsl:value-of select="ancestor::page[position() = last()]/@id" />
  </xsl:template>
-- 
Charles Knell
cknell(_at_)onebox(_dot_)com - email



-----Original Message-----
From:     Kai Weber <weber(_at_)mediaworx(_dot_)com>
Sent:     Fri, 11 May 2007 15:04:24 +0200
To:       <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject:  [xsl] Finding the path to a node

Hello,

First I would like to thank this list. So far all my
problems with XSLT could be solved with your help. Thank you!

I have a new one: I have to find the "root"-node of a node
(not the document root, but a certain root).

Let's say I want to find the root-page-node for page-node with id 4.
Result should be page-node with id 1. A list of nodes 1,2,3 is
acceptable, too.

<pages>
<page id="1">
 <page id="2">
  <page id="3">
   <page id="4">
   </page>
  </page>
 </page>
</page>
<page id="5" />
<page id="6" />
</pages>

I tried with, but this is a loop and wrong...

<xsl:apply-templates select="//page[(_at_)id='4']/ancestor:node()" />

Regards, Kai

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