fileX.xml:
<document>
<date>20071805101800</date>(yyyymmddhhmmss)
<url>folderX/foldery/</url>
<other tags that aren't to interest>
</document>
I know the shorter solution would be to have a date attribute to the <list> xml
file like <file date="2007...">file1.xml</file>
But it's a little more complicated than that, I can't really put the data as an
attribute so I need to do it with the xml-s structured like that.
10x. Cheers
----- Original Message ----
From: Dimitre Novatchev <dnovatchev(_at_)gmail(_dot_)com>
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Sent: Wednesday, May 16, 2007 2:42:58 PM
Subject: Re: [xsl] complicated sort problem
On 5/16/07, Vaduvoiu Tiberiu <vaduvoiutibi(_at_)yahoo(_dot_)com> wrote:
Similar problem with the one I had yesterday:
I need to sort the following xml:
<list>
<file>file1.xml</file>
<file>file2.xml</file>
......
<file>file100.xml</file>
</list>
each of these files have some tags (2 of which are:)
<date>20071805101800</date>(yyyymmddhhmmss)
<url>folderX/foldery/</url>
So I need to sort the first xml by the date (which is in each fileX.xml). Is
that possible? .
The short answer is: Yes.
A more specific solution with code could be produced, once the structure of the
file<N>.xml
files is known.
--
Cheers,
Dimitre Novatchev
---------------------------------------
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---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play
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