Hi All,
I am using XSL and Javascript for rendering an HTML page. The dynamic
page depends on the user selection of menu(Menu is written in
javascript). I am passing the selected menu value from Javascript to
XSL for page rendering. The value has been passed successfully to XSL
and I can see the result.
Please see the below code..
function SelectedMenu(menu_selected, toplevel)
{
Menu_Selection = toplevel;
try
{
if(toplevel != 1) // If toplevel=1 it should not go anywhere
{
var xslt = new ActiveXObject(" Msxml2.XSLTemplate");
var xslDoc = new ActiveXObject("Msxml2.FreeThreadedDOMDocument");
var xslProc;
xslDoc.async = false;
xslDoc.resolveExternals = false;
xslDoc.load ("example.xsl");
xslt.stylesheet = xslDoc;
var xmlDoc = new ActiveXObject("Msxml2.DOMDocument");
xmlDoc.async = false;
xmlDoc.resolveExternals = false;
xmlDoc.load ("installedtools.xml");
xslProc = xslt.createProcessor();
xslProc.input = xmlDoc;
xslProc.addParameter("menuselected", Menu_Selection);
xslProc.transform();
document.write (xslProc.output);
}
}
catch(e)
{
alert(e.description);
}
}
and XSL code is as follows..
<xsl:output method="html"/>
<xsl:param name="menuselected"/>
<xsl:template match="/">
and somewhere in the code I am using menuselected variable as follows.
<xsl:for-each select="/ServiceConsole/Tool">
<xsl:if test="Id=$menuselected">
Based on the menuselected value particular page details will display.
If I click on menu link the result is fine.The problem is that, if I
open link in another window through browser functionality "Open in New
Window" I am not able to see the result. Somehow I pointed out the
problem is because of document.write. If I remove that stement from js
file the result is completely gone. not even seen in the same page
itself.
Can any one please help me to fix this issue. I am very much thankful
if any one could point out the problem and let me know the process.
Thanks
Vishnu
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