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Re: [xsl] passing parameters to xsl stylesheets

2007-05-20 08:06:16
You are passing parameter !
you said to xsltproc that $toto is equal to 'from'
And it did what you wanted

In fact, it seems you want more
you want to tell to xproc to "use the value 'from' as the name of the
element where to get value"

you need to change your xslt for that


<?xml version="1.0" encoding="ISO-8859-1" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:param name="toto" />
 <xsl:template match="/note">
   <html>
    <body>
     <xsl:value-of select="*[local-name()=$toto]" />
   </body>
  </html>
 </xsl:template>
 </xsl:stylesheet>

Regards,

Xmlizer

On 5/20/07, Youness HAFFANE <youness254(_at_)gmail(_dot_)com> wrote:

Hi all
Will you  help me please?
I'm trying to pass a parameter to the following  xsl stylesheet:


<?xml version="1.0" encoding="ISO-8859-1" ?>
- <xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:param name="toto" />
- <xsl:template match="/note">
-    <html>
-    <body>
     <xsl:value-of select="$toto" />
 </body>
 </html>
</xsl:template>
</xsl:stylesheet>

The xml file which uses the xsl file is simply:

<?xml version="1.0" ?>
- <note>
   <to>Tove</to>
   <from>Jani</from>
</note>

To pass the parameter I use this command:
$ xsltproc --stringparam toto 'from' myxslfile.xsl myxmlfile.xml

The result is:
<html><body>from</body></html>
While I was expecting <html><body>Jani</body></html>

Thank you in advance!!
Youness (france)


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