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Re: [xsl] XPath MOD 10 calculation

2007-05-24 06:04:53
Abel Braaksma wrote:

   sum(
       for $i in $x[position() mod 2 = 1] return $i * 3,
       for $i in $x[position() mod 2 = 0] return $i,
       = number(substring(., string-length(.) - 1, 1))


I must be sleepy or something. "for $i in $x[position() mod 2 = 0] return $i" is the same as " $x[position() mod 2 = 0]" of course ;) and that comma should be a right parenthesis:

  sum(
      for $i in $x[position() mod 2 = 1] return $i * 3,
      $x[position() mod 2 = 0])
      = number(substring(., string-length(.) - 1, 1))

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