I find this problem rather difficult to solve with pure XSLT 1.0. This
is due to the fact, that XSLT doesn't allow to maintain variable
state
It's easy to do it in xslt1 using two stylesheets or 1 stylesheet and
the xx:nde-set() extension: first do the grouping and then do a second
pass that adds the numbering (for which you can just use position() or
xsl:number/> once the complication of sorting has beenresolved.
It is presumably possible to do it in one xslt1 stylesheet without
extensions but I suspect you'd have to be quite inefficient repeatedly
calculating the sort order, and apart from mozilla pretty much all xslt1
engines have a node-set extension.
oh what the heck I suppose I'd better do an xslt1 version, with no extensions...
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:key name="g" match="group_id" use="." />
<xsl:output indent="yes"/>
<xsl:variable name="g"
select="/sample/result/details/group_id[generate-id()=generate-id(key('g',.))]"/>
<xsl:template match="sample">
<xsl:for-each select="$g">
<xsl:sort select="."/>
<xsl:variable name="p" select="position()-1"/>
<xsl:variable name="c" select="count(key('g',$g[.<current()]))"/>
<xsl:for-each select="key('g',.)">
<output row="{$c+$p+position()}"><xsl:value-of select="."/></output>
</xsl:for-each>
<xsl:if test="position()!=last()">
<output row="{$c+count(key('g',.))+$p+1}"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
saxon sg.xml sg.xsl
<?xml version="1.0" encoding="utf-8"?>
<output row="1">250</output>
<output row="2">250</output>
<output row="3"/>
<output row="4">300</output>
David
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