xsl-list
[Top] [All Lists]

Re: [xsl] xsl:element will not create an output element, in any context

2007-05-31 06:31:33

I'm assuming this means
they will NOT be processed as XHTML elements, and hence will not
produce the result I want (which is XHTML ul and li elements)?

the code I posted would produce html or xhtml depending on whether the
default namespace in the stylesheet is null or the xhtml namespace.
If you are just rendering the result in a browser, so long as all the
elements are xhtml or all html it probably makes no difference.

David

________________________________________________________________________
The Numerical Algorithms Group Ltd is a company registered in England
and Wales with company number 1249803. The registered office is:
Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.

This e-mail has been scanned for all viruses by Star. The service is
powered by MessageLabs. 
________________________________________________________________________

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>