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Re: [xsl] Create a list of values from multiple elements

2007-07-04 02:33:38
On 7/4/07, Michael Eberhard <michael_eberhard(_at_)gmx(_dot_)at> wrote:
Hi,

I want to create a list of IDs while transforming one part of the XML document, 
as the transformation of the second part is based on the IDs chosen before.

The input XML document looks like this:

<MainElement id="0" val="10"/>
<MainElement id="1" val="20"/>
<MainElement id="2" val="30"/>
<ExtElement mid="0" ... />
<ExtElement mid="0" ... />
<ExtElement mid="1" ... />
<ExtElement mid="2" ... />

The style sheet has a parameter, which allows to specify the desired maximum 
value. If the input parameter is a value of 20, the output should look like 
this:

<MainElement id="0" val="10"/>
<MainElement id="1" val="20"/>
<ExtElement mid="0" ... />
<ExtElement mid="0" ... />
<ExtElement mid="1" ... />

My question is now, how can I store the IDs of the MainElements while 
processing them in order to have the IDs available when processing the 
ExtElements (using XSLT 1.0).


Use the identity transform with a no-op template for each of
conditions where you don't want to copy the input to the result.  The
tricky part of looking up the <MainElement> from the <ExtElement> can
be done using a key:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:param name="max" select="'20'"/>

<xsl:key name="mainElem-by-id" match="MainElement" use="@id"/>

<xsl:template match="@*|node()">
        <xsl:copy>
                <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
</xsl:template>

<xsl:template match="MainElement[(_at_)val > $max]"/>

<xsl:template match="ExtElement[key('mainElem-by-id', @mid)/@val > $max]"/>

</xsl:stylesheet>

generates:

<MainElement id="0" val="10"/>
<MainElement id="1" val="20"/>

<ExtElement mid="0"/>
<ExtElement mid="0"/>
<ExtElement mid="1"/>

cheers
andrew
--
http://andrewjwelch.com

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