I just noticed the OP is selecting the string 'x' and the string 'y' and
has the param and with-param backwards in the example. You call a
template *with* a param and the named template *has* a param.
I'm sure this was just a typo in trying to provide an example, but could
give a newbie some debugging frustration if not...
Thanks!
Angela
-----Original Message-----
From: Andrew Welch [mailto:andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com]
Sent: Wednesday, July 25, 2007 11:58 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Shorthand.
On 7/25/07, Steve <subsume(_at_)gmail(_dot_)com> wrote:
Hey there, I have a template for creating ajax links:
<xsl:template name="a">
<xsl:with-param name="href" />
<xsl:with-param name="text" />
<a href="{$href}" onClick="showData('{$href}');return
false;"><xsl:value-of select="$text" /></a> </xsl:template>
is there some shorter way to use this (XSL 1.0) template than...
<xsl:call-template name="a">
<xs:param name="href" select="'x'"/>
<xs:param name="text" select="'y'"/> </xsl:call-template>
It depends...
If x and y are selected from the current node, then you can just go:
<xsl:call-template name="a"/>
and
<xsl:template name="a">
<a href="{(_at_)x}" .....>
<xsl:value-of select="y"/>
</a>
</xsl:template>
...as the current node is the same within the named template as it is
when you call the named template.
(if not then that's the correct way.)
cheers
andrew
--
http://andrewjwelch.com
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