Jessica Hennessey wrote:
ASP Code:
Set objXmlHttp1 = Server.CreateObject("Msxml2.serverxmlhttp")
Set objDom = Server.CreateObject("MSXML2.FreeThreadedDOMDocument")
objXmlHttp1.send strSend
I miss some objXmlHttp1.open call here before the send call.
set xslt = Server.CreateObject("MSXML2.XSLTemplate")
set xslt.stylesheet = xsl
Set xslProc = xslt.createProcessor()
xslProc.input = objDom
xslProc.addParameter "order", request("order")
xslProc.transform
sOutput = xslProc.output
response.write sOutput
Not the reason why your approach does not work but consider using
xsltProc.output = Response
xsltProce.transform
here instead of transforming to a string sOutput and Response.writing
that string. You will get much less problems with character encodings
that way.
XSL Code:
<?xml version='1.0'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:param name="order"/>
<xsl:template match="/">
<xsl:for-each select="root/job">
<xsl:sort select="$order" order="ascending"/>
I think you want something alike
<xsl:sort select="*[local-name() = $order]" order="ascending"/>
but I am guessing, consider showing use how your job elements look and
what you want to order on.
--
Martin Honnen
http://JavaScript.FAQTs.com/
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