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[xsl] While copying everything, append attribute value with incremental index.

2007-08-10 20:28:23
I would like to append the value of the attribute "p" with an incremental index 
using position()
function but position() is only giving me 1s.
Input:
========
<?xml version="1.0" encoding="UTF-8"?>
<root>
    <M i="k">1</M>
    <A i="p"><B><C>5</C></B></A>
    <A i="p"><B><C>5</C></B></A>
    <A i="p"><B><C>5</C></B></A>
</root>

What I want:
=============
<?xml version="1.0" encoding="UTF-8"?>
<root>
    <M i="k">1</M>
    <A i="p_1"><B><C>5</C></B></A>
    <A i="p_2"><B><C>5</C></B></A>
    <A i="p_3"><B><C>5</C></B></A>
</root>

Output From the XSL:
=====================
<?xml version="1.0" encoding="UTF-8"?>
<root>
    <M i="k">1</M>
    <A i="p_1"><B><C>5</C></B></A>
    <A i="p_1"><B><C>5</C></B></A>
    <A i="p_1"><B><C>5</C></B></A>
</root>

XSL:
======
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Format";>
    <xsl:output method="xml" encoding="UTF-8" />

    <!-- Copy everything -->
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()">
            </xsl:apply-templates>
        </xsl:copy>
    </xsl:template>
    
    <xsl:template match="@i[parent::A]">
        <xsl:attribute name="i"><xsl:value-of select="concat(., 
'_')"/><xsl:value-of
select="position()"/></xsl:attribute>
    </xsl:template>
        
</xsl:stylesheet>


thx!


       
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