The output you are asking for is not legal XML (see below), so I am not clear
on what to advise.
XML requires that all elements be properly nested. The output you have
specified:
<item>
<b>
<label>1.1</label>
<para>Grundbegriffe
</b>
<xref pointer="p0002">2</xref>
</para>
</item>
has the <b> element overlapping the <para> element.
In XML, you can't have "<b><para></b></para>", and that's what you've specified
as your desired output.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Byomokesh Sahoo <sahoo(_dot_)byomokesh(_at_)gmail(_dot_)com>
Sent: Wed, 5 Sep 2007 14:46:17 +0530
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Search text and write the code
Hi All,
I have some problem in my project. I need text or number search in
text and write the code. Is it possible through XSLT?
My XML
=====
<o1item><emphasis style="b">1.1 Grundbegriffe</emphasis> <hotlink
xref="p0002" xidtype="page">2</hotlink></o1item>
XSL File
=======
<xsl:template match="o1item">
<xsl:text>
</xsl:text><item>
<xsl:call-template name="labelstring">
<xsl:with-param name="Text" select="."/>
</xsl:call-template>
<para><xsl:apply-templates /></para>
</item>
</xsl:template>
<xsl:template name="labelstring">
<xsl:param name="Text"/>
<xsl:choose>
<xsl:when test="contains($Text, ' ')">
<label>
<xsl:value-of select="substring-before($Text, ' ')" />
</label>
</xsl:when>
</xsl:choose>
</xsl:template>
On the base my style sheet output is
<item><label>1.1</label><para><b>1.1 Grundbegriffe</b><xref
pointer="p0002">2</xref></para></item>
But I need output is..........
<item><b><label>1.1</label> <para>Grundbegriffe</b><xref
pointer="p0002">2</xref></para></item>
Please anyone suggest me what can i do.
Thanks
Byomokesh Sahoo
Om Trayambakam Yajaamahe Sugandhim Pushtivardhanam
Urvaarukamiva Bandhanan Mrytor Muksheeya Mamritaat
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