You are trying to select a node called l.000
You want the variable as a string value, not a selection
Try this...
<xsl:variable name="numberFormat" select="'l.000'" />
-----Original Message-----
From: Nick James [mailto:nicholasjames2(_at_)hotmail(_dot_)com]
Sent: 07 September 2007 15:54
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] format-number using variable format string
My problem is that I want to format some numbers in an xml file in a
fixed way, yet one which I can change relatively easily if need be. If
we have the file problem.xml:
<?xml version="1.0" encoding="utf-8"?>
<numbers>
<number>22222.444444</number>
<number>2.5555555</number>
<number>999999.444444</number>
<number>22222.444444</number>
</numbers>
and the file problem.xsl:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="text" />
<xsl:template match="number">
<xsl:variable name="numberFormat" select="l.000" />
<xsl:value-of select='format-number(text(), $numberFormat)' />
</xsl:template>
</xsl:stylesheet>
the output is
$ xsltproc problem.xsl problem.xml
22222
3
999999
22222
when I would have expected to see 3 dps on the numbers.
I keep on having this sort of problem with xsl(t?) - there are a hundred and
one good uses for it, but I end up getting completely bogged down.
Any answers?
NickJ
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