On Fri, Sep 21 2007 16:28:47 +0100, rocketraman(_at_)fastmail(_dot_)fm wrote:
Tony Graham wrote:
On Fri, Sep 21 2007 08:51:13 +0100, rocketraman(_at_)fastmail(_dot_)fm wrote:
...
I'm still trying to get my head around what you want to do with your
template, but the likely reasons that your simplification doesn't work
are:
I should have provided the output I wanted (obviously ignoring
templates applied to irrelevant nodes). Here it is (basically grouping
all nodes between g1 and g2 into a hierarchical structure).
<r>
<n1/>
...
<n2/>
<group>
<g1/>
...
<g2/>
</group>
<group>
<g1/>
...
<g2/>
</group>
<n3/>
...
<n4/>
</r>
I stated in my original email, but didn't emphasize, that there are an
arbitrary number of nodes between g1 - g2, n1 - n2, and n3 - n4 (my
example nodes were badly named).
It may be simpler if you do it all using ">>":
<xsl:template match="r">
<xsl:copy>
<xsl:apply-templates select="*[../g1[1] >> .]"/>
<xsl:for-each-group
select="g1[1] |
*[(. >> ../g1[1]) and (../g2[last()] >> .)] |
g2[last()]"
group-ending-with="g2">
<group>
<xsl:apply-templates select="current-group()"/>
</group>
</xsl:for-each-group>
<xsl:apply-templates select="*[. >> ../g2[last()]]"/>
</xsl:copy>
</xsl:template>
(The logic might be clearer if the predicates used "<<" instead, except
that "<<" has to be written as "<<".)
Regards,
Tony Graham.
======================================================================
Tony(_dot_)Graham(_at_)MenteithConsulting(_dot_)com
http://www.menteithconsulting.com
Menteith Consulting Ltd Registered in Ireland - No. 428599
Registered Office: 13 Kelly's Bay Beach, Skerries, Co. Dublin, Ireland
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Menteith Consulting -- Understanding how markup works
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