RE: [xsl] Checking alphabetical order

> For my own curiousity, does XSLT 2.0/XPath 2.0 get around 
> this limitation?
In 1.0, the only operation that does alphabetic order comparison is sorting.

In 2.0, you can use the comparison operators < and > (or lt, gt) to compare
strings, so there's a much wider range of possibilities. In fact, the
solution you provide for numbers:

Elements/Element[. &lt; preceding-sibling::node()]

will do a string comparison rather than a numeric comparison in 2.0. It's
wrong, however: you should write

Elements/Element[. &lt; preceding-sibling::*[1]]

Michael Kay
http://www.saxonica.com/


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