Assuming your concats and substrings are correct, you want to create a template
to match "submissionDeadline" and apply the template from your stylesheet at
the appropriate point.
Replace $currentTime with ".", which represents the current node.
<xsl:template match="submissionDeadline"><xsl:value-of
select="concat(substring(.,
,4),substring(.,6,2),substring(.,9,2),substring(.,12,2),substring
(.,15,2),substring.,18,2))"/></xsl:template>
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Aaron Johnson <artpunx(_at_)gmail(_dot_)com>
Sent: Thu, 4 Oct 2007 18:25:39 +0100
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] selecting a node to concatenate
I have a node in my XML which contains a date string. I want to
concatenate it into an integer. I can do the concat part using
substrings but can't work out how to select the node in the first
instance!
The XML looks like this...
2027-10-04T09:00:00.0000000-00:00</submissionDeadline>
..if I pass it to the stylesheet as a param or variable I can concatanate it...
<xsl:variable
name="currentTime">2007-10-04T09:00:00.0000000+01:00</xsl:variable>
<xsl:variable name="currentTimeString"
select="concat(substring($currentTime, 1,4),substring($currentTime,
6,2),substring($currentTime,
9,2),substring($currentTime,12,2),substring($currentTime,15,2),substring($currentTime,18,2))"/>
.. to make it look like this...
20071004090000
I need a way to select the <submissionDeadline> nodes content to get a
similar result.
Any ideas? Thanks for any suggestions...
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