Hi,
I am making attempts to make the output of the transformed XML to be
able to display different images based on the nodes and string length.
Below is the XSLT:
XSLT:
<xsl:template match="book">
<xsl:variable name="rendition">
<xsl:value-of select="./@rendition"/>
</xsl:variable>
<div>
<p>
<xsl:choose>
<xsl:when test="$rendition!=''">
<div>
<xsl:attribute name="class">
<xsl:value-of select="$rendition"/>
</xsl:attribute>
<xsl:if
test="string-length(child::text())<'25'">
<xsl:attribute name="style">
background-image:url('<xsl:value-of
select="./@rendition"/>.png')
</xsl:attribute>
</xsl:if>
<xsl:if test="string-length('25 ' <
child::text() < '50')">
<xsl:attribute name="style">
background-image:url('<xsl:value-of
select="./@rendition"/>_med.png') </xsl:attribute>
</xsl:if>
<xsl:if test="count(child::p) > 1">
<xsl:attribute name="style">
background-image:url('<xsl:value-of
select="./@rendition"/>_large.png') </xsl:attribute>
</xsl:if>
<p>
<xsl:call-template name="rend"/>
<xsl:apply-templates/>
</p>
</div>
</xsl:when>
<xsl:otherwise>
<!--Don't display anything-->
</xsl:otherwise>
</xsl:choose>
</p>
</div>
</xsl:template>
XML:
<book topic="Technology" rendition="xslt" author="Tennison, Jeni"
title="Beginning XSLT">
<p>New York: Apress, 2002.</p>
<p>The book serves as an introduction to XSLT based on the examples
of a television
program set. A resourceful book for those new to the technology.</p>
</book>
I want to use the code displayed above (XML) to display the file name
with the name of xslt_large, and now in the HTML source it does not
display that, even though the code above has two <p> tags. Can anyone
please help me out?
Anything is appreciated.
Alice
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