xsl:perform-sort is delivering a sequence of strings, and your xsl:variable
is then concatenating these into a single text node. Use <xsl:variable
as="xs:string*"/> if you want a sequence of strings, or
as="attribute(date)*" if you want a sequence of attribute nodes.
Michael Kay
-----Original Message-----
From: Merico Raffaele [mailto:raffaele(_dot_)merico(_at_)less(_dot_)ch]
Sent: 22 October 2007 12:05
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] xsl:perform-sort sequence problem
Dear Community
I am using SaxonB 8.9 and I have the following
xsl:perform-sort/sequence problem.
<xsl:variable name="data">
<item id="1">
<departure date="2007-10-22">
<returning date="2007-10-23"/>
<returning date="2007-10-24"/>
</departure>
</item>
<item id="2">
<departure date="2007-10-22">
<returning date="2007-10-22"/>
<returning date="2007-10-24"/>
</departure>
</item>
</xsl:variable>
*** OK-Case:
When I run the following statements I get an expected result of:
<xsl:variable name="result"
select="distinct-values($data/item/departure[(_at_)date eq
'2007-10-22']/returning/@date)"/> <xsl:value-of
select="count($result)"/> <xsl:value-of select="$result"
separator=", "/>
=> 3
=> 2007-10-23,2007-10-24,2007-10-22
*** ??-Case:
When I try to sort the same sequence the distinct-values
become one single
string:
<xsl:variable name="result">
<xsl:perform-sort
select="distinct-values($data/item/departure[(_at_)date
eq '2007-10-22']/returning/@date)">
<xsl:sort/>
</xsl:perform-sort>
</xsl:variable>
<xsl:value-of select="count($result)"/>
<xsl:value-of select="$result" separator=", "/>
=> 1
=> 2007-10-22 2007-10-23 2007-10-24
Can any body please helping me to clarify my misunderstanding
of the xsl:perform-sort.
Many thanks in advance
Raffaele
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