Re: [xsl] Sorting a XML file with XSL

Buddhi Dananjaya wrote:

  Hi

> Following is my sample XML file, I want to sort this base on
> <comment> tag and make a new XML file using a style sheet
  You can use the Modified Identity pattern:

    <xsl:output indent="yes"/>

    <!-- Identity transform -->
    <xsl:template match="node()">
       <xsl:copy>
          <xsl:copy-of select="@*"/>
          <xsl:apply-templates select="node()"/>
       </xsl:copy>
    </xsl:template>

    <xsl:template match="root">
       <xsl:copy>
          <xsl:copy-of select="@*"/>
          <xsl:apply-templates select="*">
             <xsl:sort select="data/comment"/>
          </xsl:apply-templates>
       </xsl:copy>
    </xsl:template>

  The data/comment contents are not unique.  If you want to order a
second field to perform more precise sorting, you can do so using a
second xsl:sort instruction.  For instance, if you want to sort on
comment then on @name:

    <xsl:apply-templates select="*">
       <xsl:sort select="data/comment"/>
       <xsl:sort select="data/@name"/>
    </xsl:apply-templates>

  Regards,

--drkm
























      
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