From what you are writing I understand you are using XSLT 1.0, because
in XSLT 2.0 your expression would give an error.
The way to do this is simply:
select = "normalize-space(A)"
which will give you the text content of node A (and thus of all its
children).
HTH,
Cheers,
-- Abel Braaksma
Kolací Tomáš wrote:
Hi!
I'd like to fill variable textOnly by normalized string of all text of the
element A. I'm just wondering is there any way, I could write it as one XPath
expression, like:
<xsl:variable name="textOnly" select="normalize-space(A//text())"/>
(but here only the first text node is used)?
Please note, I'm interested only in the "one XPath expression" way, I know how
solve problem in different way*.
Thanks, Tomas
*like:
<xsl:variable name="textOnlyPre">
<xsl:copy-of select="A//text()">
</xsl:variable>
<xsl:variable name="textOnly" select="normalize-space($textOnlyPre)"/>
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--