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Re: [xsl] Find the node with maximum elements

2007-11-03 12:20:32
At 2007-11-03 12:05 -0700, Avaneesh Ramprasad wrote:
I have a requirement to write a xsl transformation to find the node which has the maximum number of elements
...
The xsl should return Honda and Mitsubishi

Not sure where you are having the problem, but XSLT 2 provides the max() function that makes this very easy.

I hope the solution below helps. You can optimize the speed by putting the max value into a variable and testing against that, but I just wrote the XPath as I said the requirement aloud, so this is what I ended up with.

. . . . . . Ken

T:\ftemp>type avaneesh.xml
<Sample>
    <Toyota>
          <Car>Camry</Car>
          <Car>Corrola</Car>
     </Toyota>
     <Honda>
            <Car>Accord></Car>
          <Car>Civic</Car>
          <Car>Pilot</Car>
     </Honda>
     <Mitsubishi>
        <Car>Lancer</Car>
        <Car>Lancer</Car>
        <Car>Lancer</Car>
     </Mitsubishi>
    <Hyundai>
        <Car>Sonata</Car>
        <Car>Accent</Car>
</Hyundai>
</Sample>

T:\ftemp>type avaneesh.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                xmlns:xsd="http://www.w3.org/2001/XMLSchema";
                exclude-result-prefixes="xsd"
                version="2.0">

<xsl:output method="text"/>

<xsl:template match="/">
  <xsl:for-each select="/Sample/*[count(Car)=max(/Sample/*/count(Car))]">
    <xsl:value-of select="name(.)"/>
    <xsl:text>
</xsl:text>
  </xsl:for-each>
</xsl:template>

</xsl:stylesheet>
T:\ftemp>xslt2 avaneesh.xml avaneesh.xsl con
Honda
Mitsubishi

T:\ftemp>

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