Hi,
I agree - a nice solution.
But the solution would be even nicer if we had more access to the key.
Once we have the key we can select all elements that have 0 cars, or 1 car, or
6 cars, but not a run-time function of the key use value such as what we want:
the largest value of 'use' in this document. So we do what is shown below -
scan through the elements to find the maximum value even though the information
is _already in the key_. (I doubt that I have the terminology correct.)
I would like something like:
<xsl:for-each select="key('cars', max())">
<xsl:for-each select="key('cars', sort(ascending))">
or if 'use' is alpha, something like:
<xsl:for-each select="key('carnames', not(contains('xyz'))">
Is this a good addition for XSLT 2.1? It seems to me this allows both
simplified and more efficient code.
Brad.
-----Original Message-----
From: Mukul Gandhi [mailto:gandhi(_dot_)mukul(_at_)gmail(_dot_)com]
Sent: November 5, 2007 1:02 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Find the node with maximum elements
Nice solution, Scott.
On 11/5/07, Scott Trenda <Scott(_dot_)Trenda(_at_)oati(_dot_)net> wrote:
This may be better represented with 2.0's grouping facilities, but
here's the 1.0 solution I'd use to alleviate Mukul's concerns
(building off Michael's response with <xsl:sort/>):
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:key name="cars" match="*[Car]" use="count(Car)"/>
<xsl:template match="Sample">
<xsl:variable name="max-cars">
<xsl:for-each select=".//*[Car]">
<xsl:sort select="count(Car)" data-type="number"/>
<xsl:if test="position() = last()">
<xsl:value-of select="count(Car)"/>
</xsl:if>
</xsl:for-each>
</xsl:variable>
<xsl:for-each select="key('cars', $max-cars)">
<!-- do whatever you'd do with the results here -->
<xsl:value-of select="name()"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
~ Scott
--
Regards,
Mukul Gandhi
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