I'm guessing that you want something like this:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html"/>
<xsl:template match="head">
<h1>
<xsl:apply-templates/>
</h1>
</xsl:template>
<xsl:template match="list">
<ul>
<xsl:apply-templates/>
</ul>
</xsl:template>
<xsl:template match="item">
<li>
<xsl:apply-templates/>
</li>
</xsl:template>
</xsl:stylesheet>
<xsl:value-of select="child::item"/> in your "list" template will only
give you the text values of those child nodes. You were missing the HTML
structure. Also, you can omit the <xsl:value-of/> here; the built-in
template for text nodes is to select the value of the node. Just
<xsl:apply-templates/> inside an HTML element in your template.
~ Scott
-----Original Message-----
From: Alice Ju-Hsuan Wei [mailto:ajwei(_at_)indiana(_dot_)edu]
Sent: Tuesday, November 06, 2007 5:57 PM
To: xsl-list
Subject: [xsl] Generate a List
Hi,
I am trying to use the XSLT to generate something simple like a list
and output it to HTML with <ul> and <li> tags.
This is my XSLT:
<xsl:template match="head">
<p>
<xsl:apply-templates/>
</p>
</xsl:template>
<xsl:template match="list">
<xsl:value-of select="child::item"/>
</xsl:template>
My XML:
<head>Things to do</head>
<list>
<item>Wash the dog</item>
<item>Take out the trash</item>
<item>Check out books on XSLT</item>
<item>Go to the bank</item>
<item>Pay bills</item>
</list>
Output:
<p class="">Things to do</p>
Wash the dog Take out the trash Check out books on XSLT Go to the
bank Pay bills
<br>
Can anyone please tell me what is wrong with my code?
Thanks to those who can help.
Alice
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