On 07/11/2007, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
It seems that you are trying to obtain the scalar product of
two vectors:
X = {x1, x2, ... , xn}
Y = {y1, y2, ... , yn}
X.Y = x1.y1 + x2.y2 + ... + xn.yn
If that is indeed the requirement (and I wasn't able to work it out from the
posting) then it can be done in XPath 2.0 (without any help from FXSL) as
sum(for $i in 1 to count($x) return $x[$i] * $y[$i])
My guess was for the sum of the cross product:
sum(for $a in $x, $b in $y return $a * $b)
...i guess we'll find out at some point
--
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/
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