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Re: [xsl] Using for-each on user arguments [was: Re: Passing a list of arguments]

2007-11-09 07:07:03
On 09/11/2007, Mathieu Malaterre <mathieu(_dot_)malaterre(_at_)gmail(_dot_)com> 
wrote:
Ok

  Maybe with a more explicit title I'll get some help. Basically I am
trying to avoid writting an infinite <xsl:if test="arg1 or arg2 or
arg3 ... ">. So as a procedurial guy I thought of doing a list of user
defined values to iterate over. This lead me to (*), but of course
this cannot be working since I got mixup in between my user input arg
list, and the real XML document I am trying to parse.

  Thanks for help
-Mathieu

(*)
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
version="2.0">
  <xsl:output method="xml" indent="yes" encoding="UTF-8"/>
  <xsl:variable name="sections-list">
    <args>
      <arg>C.8.7.1.1.2</arg>
      <arg>C.8.14.1.1</arg>
    </args>
  </xsl:variable>
  <xsl:template match="article">
    <xsl:param name="extract-section"/>
    <el>
      <xsl:value-of select="$extract-section"/>
    </el>
  </xsl:template>
  <xsl:template match="/">
    <e>
      <xsl:for-each select="$sections-list/args/arg">
        <xsl:apply-templates select="article">
          <xsl:with-param name="extract-section" select="."/>
        </xsl:apply-templates>
      </xsl:for-each>
    </e>
  </xsl:template>
</xsl:stylesheet>

I think you are asking for:

<xsl:apply-templates select="article/*[name() = $sections-list/args/arg]"/>

...so you want the children of <article> in your input XML that have
the same name as any of the <arg> elements in your $sections-list

If that not what you want, you need to approach your question from the
opposite angle - show what you want to achieve and not how you think
you need to get there.


cheers
-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/

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