[xsl] question about a past problem (solved by Ken)

Hello list!

I try to solve a problem by my own which Ken G. Holman solved  
fortunately solved a few days ago. But for improving my not really  
destinctive XSLT skills I tried to solve the problem by my own. But  
now I am fighting with the problem again. I hope the list will be not  
too impatient with me :-)
Here is the flat XML-code:

<Root>
    <element>
        <h1>h1</h1>
        <h2>h2_1</h2>
        <para>para_h2_1</para>
        <para>para_h2_1</para>
        <para>para_h2_1</para>
        <para>para_h2_1</para>
        <para>para_h2_1</para>
        <para>para_h2_1</para>
        <para>para_h2_1</para>
        <h2>h2_2</h2>
        <h3>h3_1</h3>
        <para>para_h3_1</para>
        <h4>h4_1</h4>
        <h5>h5_1</h5>
        <para>para_h5_1</para>
        <h5>h5_2</h5>
        <note>note_h5_2</note>
        <para>para_h5_2</para>
        <h4>h4_2</h4>
        <para>para_h4_2</para>
        <para>para_h4_2</para>
        <para>para_h4_2</para>
        <note>note_h4_2</note>
        <h3>h3_2</h3>
        <para>para_h3_2</para>
        <para>para_h3_2</para>
        <para>para_h3_2</para>
        <h4>h4_3</h4>
        <para>para_h4_3</para>
        <para>para_h4_3</para>
        <para>para_h4_3</para>
        <h5>h5_3</h5>
        <para>para_h5_3</para>
        <para>para_h5_3</para>
    </element>
</Root>

I am using this stylesheet for transformations:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";  
version="2.0">
    <xsl:output indent="yes" encoding="UTF-8"/>

    <xsl:template match="/">
        <set>
            <book>
                <bookinfo/>
                <author/>
                <xsl:apply-templates/>
            </book>
        </set>
    </xsl:template>

    <xsl:template match="Root">
        <xsl:apply-templates/>
    </xsl:template>

    <xsl:template match="element">
        <title>
            <xsl:apply-templates select="h1"/>
        </title>
        <chapter>
            <xsl:apply-templates select="h2[1]"/>
        </chapter>
    </xsl:template>

    <xsl:template match="h2">
        <title>
            <xsl:apply-templates/>
        </title>
        <xsl:for-each-group select="following-sibling::*"  
group-starting-with="h2|h3|h4|h5">
            <xsl:apply-templates select="current-group()"/>
        </xsl:for-each-group>
    </xsl:template>

    <xsl:template match="h3">
        <xsl:element name="sect{number(substring-after(name(.),'h')) - 2}">
            <title>
                <xsl:apply-templates/>
            </title>
            <para>
                <xsl:apply-templates  
select="current-group()[self::para]/node()"/>
            </para>
        </xsl:element>
    </xsl:template>

    <xsl:template match="h4">
        <xsl:element name="sect{number(substring-after(name(.),'h')) - 2}">
            <title>
                <xsl:apply-templates/>
            </title>
            <xsl:for-each select="current-group()[para]">
                <para>
                    <xsl:apply-templates  
select="current-group()[self::para]/node()"/>
                </para>
            </xsl:for-each>
        </xsl:element>
    </xsl:template>

    <xsl:template match="h5">
        <xsl:element name="sect{number(substring-after(name(.),'h')) - 2}">
            <title>
                <xsl:apply-templates/>
            </title>
            <para>
                <xsl:apply-templates  
select="current-group()[self::para]/node()"/>
            </para>
        </xsl:element>
    </xsl:template>
</xsl:stylesheet>

But something is wrong with it but I cannot see the mistake at the  
moment. My problem is, that the textnodes are outputted after every  
<sectxx>. This should come from the <xsl:apply-templates  
select="current-group()"/> but I donnot really want them to be  
displayed.
I would be very thankful for every hint from the experts.

Thanks,
Andreas


--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--